the current in the adjoining circuit will be?

\frac{1}{45}

ampere

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\frac{1}{15}

ampere

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\frac{1}{10}

ampere

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\frac{1}{5}

ampere

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Solution

The correct option is C $\frac{1}{10}$ ampere
$R_{e q u i v a l e n t} = \frac{(30 + 30) 30}{(30 + 30) + 30} = \frac{60 \times 30}{90} = 20 Ω$

$∴ i = \frac{V}{R} = \frac{2}{20} = \frac{1}{10} a m p e r e$

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