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Using Lenz's Law

The current i...

Question

The current in the loop at $t = 0$ due to induced emf is

0.16

, clockwise

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0.08 A

, clockwise

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0.08 A

,anticlockwise

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zero

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Solution

The correct option is A $0.16$ , clockwise
When your right thumb points in the direction opposite to the change in B your fingers curl in the direction of the induced electric field. (or potential difference) as shown in Equivalent circuit figure

Equivalent resistance $R = 1 \times (0.4 + 0.2 + 0.4) = 1 Ω$

Induced emf $e = \frac{d (B A)}{d t} = l_{1} l_{2} \frac{d B}{d t} = l_{1} l_{2} \frac{d 2 T}{d t} = {2 l}_{1} l_{2}$

At $t = 0$ , $e = 2 \times 0.2 \times 0.4 = 0.16 V$

current $I = \frac{e}{R} = \frac{0.16}{1} = 0.16 A . . (c l o c k w i s e)$

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In the arrangement shown in given figure current from A to B is increasing in magnitude. Induced current in the loop will

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Table 1	Table 2
(a) If current is increased	(p) Induced current in loop is clockwise
(b) If current is decreased	(q) Induced current in loop is anticlockwise
(c) If loop is moved away from the wire	(r) Wire will attract the loop
(d) If loop is moved towards the wire	(s) wire will repel the loop

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