MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Wheatstone Bridge

The current t...

Question

The current through the 4Ω resistor shown in the figure is.

A

0 A

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

1 A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

3 A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

2 A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 0 A
Let's assume the currents to be like this

Applying KVL on ADCA
$+ 3 - 3 i_{1} + 4 (i_{2} - i_{1}) = 0$
$7 i_{1} - 4 i_{2} = 3$ ....(1)
Applying KVL on ACBA
$- 4 (i_{2} - i_{1}) - 6 i_{2} + 6 = 0$
$10 i_{2} - 4 i_{1} = 6$ ....(2)
Solving (1) and (2) we get
$i_{1} = 1 A, i_{2} = 1 A$
$∴ i_{2} - i_{1} = 0 A .$
Current through 4Ω resistor is 0 A.

Suggest Corrections

thumbs-up

0

Similar questions

Q. The current through the

8 Ω

resistor (shown in figure) is :

Q. The current through the 10

Ω

resistor shown in figure is

Q. Consider the network shown in the figure. The current in

2 Ω

resistor is 6A. Then power delivered in

12 Ω

resistor is (4n) W .find n. ___

Q. The current through

10 Ω

resistor shown in figure is

Q. In the arrangement shown in figure, the current through

5 Ω

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Wheatstone Bridge

PHYSICS

Watch in App

explore_more_icon

Explore more

Wheatstone Bridge

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon