Question

The current through the ideal diode as show in the figure is:

• A. 0 A
• B. 0.02 A
• C. 0.04 A
• D. 1/30 A

Answer 1

The correct option is D 1/30 A

The potential difference between the two ends of the system is $V=\left(10-5\right)=5\text{Volt}$

The resistance is $R=150\Omega$

Therefore, the current in the system, $I=\frac{V}{R}=\frac{5}{150}=\frac{1}{30}A$