Question

The curved surface area of a right circular cylinder of height $14cm$ is $88c{m}^2$. Find the diameter of the base of the cylinder. (Assume $\mathrm{\pi }=\frac{22}{7}$)

Answer 1

Step 1: Find the radius of cylinder.

Given : Height of cylinder$\left(h\right)=14cm$

Curved Surface Area of cylinder$\left(CSA\right)=88c{m}^2$

Let the radius of the cylinder be $rcm$

Curved Surface Area $=2\mathrm{\pi rh}$

$$\begin{gathered} \Rightarrow 2\mathrm{\pi rh}=88 \\ \Rightarrow 2\mathrm{x}\frac{22}{7}\mathrm{x}\mathrm{r}\mathrm{x}14=88 \\ \Rightarrow 88\mathrm{r}=88 \\ \Rightarrow \mathrm{r}=1\mathrm{cm} \end{gathered}$$

Step 2: Find the diameter of the base of cylinder.

Since diameter is $2$times the radius

Therefore , diameter $=2xr$

$$\begin{gathered} =2x1 \\ =2cm \end{gathered}$$

Hence, the diameter of the base of the cylinder is $2cm$.