Question

The cylindrical tube of a spray pump has a cross section of $8$ $c{m}^2$ one end of which has $40$ fine holes each of area ${10}^{-8}{m}^2$. If the liquid flows in side the tube with a speed of $0.15$m $mi{n}^{-1}$ the speed with which the liquid is ejected through the holes is?

• A. $50$m/s
• B. $5$m/s
• C. $0.54$m/s
• D. $0.5$m/s

Answer 1

The correct option is B $5$m/s

by equation of continuity

$A_1{V}_1=A_2{V}_2$

$8\times {10}^{-4}{m}^2\times 0.15\frac{m}{min}=40\times {10}^{-8}{m}^2\times V_{m/min}$

$\frac{0.03\times {10}^4}{60}=Vinm/s$

$V=5m/s$