Question

The de Brogile wavelength of a particle with mass 1 g and velocity $100$is:

• A. $6.63\times {10}^{-33}$
• B. $6.63\times {10}^{-34}$
• C. $6.63\times {10}^{-35}$
• D. $6.63\times {10}^{-36}$

Answer 1

The correct option is A $6.63\times {10}^{-33}$

The correct option is A

we know that $p=\frac{h}{\lambda }$(de-brodglieEquation)

$\lambda =\frac{h}{mv}$(P=mv)

Given $v=100m{s}^{-1}$ and $m=1$g

So,

$\frac{6.626\times {10}^{34}{m}^{2}kg/s}{{10}^{-3}\times 100m{s}^{-1}}$

$=6.626\times {10}^{-33}$