Question

The de-Broglie's wavelength of electron present in first Bohr orbit of $H$ atom is?

• A. $4\times 0.529\stackrel{o}{A}$
• B. $2\pi \times 0.529\stackrel{o}{A}$
• C. $\frac{0.529}{2\pi }\stackrel{o}{A}$
• D. $0.529\stackrel{o}{A}$

Answer 1

The correct option is B $2\pi \times 0.529\stackrel{o}{A}$

First Bohr orbit of 'H' atom has radius $r=0.529A^o$

Also, the angular momentum is quantized.

$mvr=\frac{h}{2\pi }$

$2\pi r=\frac{h}{mv}=\lambda$

$\lambda =2\pi \times 0.529\stackrel{o}{A}$

The de Broglie's wavelength of electron present in first Bohr orbit of H atom is $2\pi \times 0.529\stackrel{o}{A}$.

So, the correct option is $B$