Question

The de-Broglie wavelength associated with the motion of earth orbiting around the sun at a speed of $3\times {10}^6$ m/s is:

[mass of earth $6\times {10}^{24}Kg$]

• A. $3.68\times {10}^{-65}m$
• B. $3.68\times {10}^{-56}m$
• C. $4.76\times {10}^{-65}m$
• D. $4.76\times {10}^{-56}m$

Answer 1

The correct option is A $3.68\times {10}^{-65}m$

De Broglie wavelength is calculated as

$\lambda =\frac{h}{mv}$

$\lambda =\frac{6.62\times {10}^{-34}}{6\times {10}^{24}\times 3\times {10}^6}$

$\Rightarrow \lambda =3.68\times {10}^{-65}m$

Hence, the correct option is $A$