The de-Broglie wavelength of a neutron at 27∘C is λ . What will be its wavelength at 927∘C
λ2
λ3
λ4
λ9
λneutron∝1√T⇒λ1λ2=√T2T1 ⇒λλ2=√(273+927)(273+27)=√1200300=2⇒λ2=λ2