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Question

The de-Broglie wavelength of a neutron at 27C is λ. What will be its wavelength at 927C

A
λ2
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B
λ3
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C
λ4
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D
λ9
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Solution

The correct option is A λ2
12mV2=32kT
mV=3mKT
λ=hp=hmV=h3mKT
λ α=1T
λ1λ2=T2T1=273+927273+27=2
λ2=λ12=λ2.

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