Question

The de-Broglie wavelength of a particle of mass 6.63 g moving with a velocity of $100m{s}^{-1}$ is:

• A. ${10}^{-33}m$
• B. ${10}^{-35}m$
• C. ${10}^{-31}m$
• D. ${10}^{-25}m$

Answer 1

Answer: (A)

${10}^{-33}m$

$\lambda =\frac{h}{mv}$

where, $\lambda =$ de-Broglie wavelength

$m=$ mass of particle

$v=$ velocity of particle

$\lambda =\frac{6.625\times {10}^{-34}\times 1000}{6.63\times 100}={10}^{-33}m$