Question

The deBroglie wavelength associated with a particle of mass $m$ and energy $E$ is $\frac{h}{\sqrt{2mE}}$. The dimensional formula of Planck's constant h is

• A. $\left[M^2{L}^2{T}^{-2}\right]$
• B. $\left[M{L}^2{T}^{-1}\right]$
• C. $\left[ML{T}^{-2}\right]$
• D. $\left[M{L}^2{T}^{-2}\right]$

Answer 1

The correct option is B $\left[M{L}^2{T}^{-1}\right]$

Planck constant $=h=\lambda \sqrt{2mE}=L\sqrt{M(M{L}^2{T}^{-2)}}=\left[M{L}^2{T}^{-1}\right]$