The decomposition of certain mass of CaCO3 gave 11.2 dm3 of CO2 gas at STP. The mass of KOH required to completely neutralise the gas is :
A
56 g
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B
28 g
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C
42 g
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D
20 g
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Solution
The correct option is B 56 g CaCO3→CaO+CO2(1/2mole)2KOH+CO2→K2CO3+H2O2→11moleofCO2reactwith2moleofKOH1/2moleofCO2reactwith1moleofKOHso,massofKOHrequired=56gm