Question

The decomposition of hydrocarbon follows the equation, $k=(4.5\times {10}^{11}{s}^{-1})e^{-28000K/T}$.
Calculate $E_a$.

Answer 1

The expression for $k$ is as follows:

$k=(4.5\times {10}^{11}{s}^{-1})e^{-28000K/T}$

Comparing it with Arrhenius equation, we get
$k=A{e}^{-E_a/RT}$

$\frac{E_a}{R}=28000K$

The activation energy $=E_a=28000\times 8.314=232792J/mol=232.792kJ/mol$