The decomposition of N2O4 to NO2 is carried out at 280oC in chloroform. When equilibrium is reached, 0.2 mol of N2O4 and 2×10−3 mol of NO2 are present in a 2L solution. The equilibrium constant for the reaction N2O4⇌2NO2 is:
A
1×10−2
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B
2×10−3
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C
1×10−5
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D
2×10−5
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Solution
The correct option is D1×10−5 N2O4⇌2NO2 Initial l 0 Final 1-x 2x 1−x=0.2mol2x=2×10−3mol [N2O4]=0.22=0.1M[N2]=2×10−32=10−3M K=[NO2]2[N2O4]=(10−3)20.1=10−5