The decomposition reaction of $S O_{2} C l_{2}$ is the first order reaction. It's concentration gets halved in $60$ minutes, what is its rate constant value?

0.1155

m i n u t e^{- 1}

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0.07676

m i n u t e^{- 1}

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0.7676

m i n u t e^{- 1}

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0.01155

m i n u t e^{- 1}

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Solution

The correct option is B $0.01155$ $m i n u t e^{- 1}$
Since its concentration gets halved in 60 minutes,
Its half-life period is 60 minutes.

For first order reaction, the rate constant is given as follow:
$K = \frac{0.693}{t_{1 / 2}} = \frac{0.693}{60 m i n u t e s} = 0.01155 m i n u t e^{- 1}$

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The decomposition reaction of SO2Cl2 is the first order reaction. It's concentration gets halved in 60 minutes, what is its rate constant value?

The correct option is B 0.01155 minute−1Since its concentration gets halved in 60 minutes,Its half-life period is 60 minutes.For first order reaction, the rate constant is given as follow:K=0.693t1/2=0.69360 minutes=0.01155 minute−1

The decomposition reaction of $S O_{2} C l_{2}$ is the first order reaction. It's concentration gets halved in $60$ minutes, what is its rate constant value?

The correct option is B $0.01155$ $m i n u t e^{- 1}$
Since its concentration gets halved in 60 minutes,
Its half-life period is 60 minutes.

For first order reaction, the rate constant is given as follow:
$K = \frac{0.693}{t_{1 / 2}} = \frac{0.693}{60 m i n u t e s} = 0.01155 m i n u t e^{- 1}$