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Hyperconjugation

The decreasin...

Question

The decreasing order of the stabilities of the following alkenes is:

(i) > (i i) > (i i i) > (i v)

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(i v) > (i i i) > (i i) > (i)

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(i) > (i i) > (i v) > (i i i)

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(i) > (i v) > (i i i) > (i i)

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Solution

The correct option is B $(i v) > (i i i) > (i i) > (i)$
Stability of alkenes $\propto$ Hyperconjugative structures $\propto$ Number of $α -$ Hydrogens

$(i)$

Number of $α -$ Hydrogen = 0

$(i i)$

No of $α -$ Hydrogen = 6

$(i i i)$

Number of $α -$ Hydrogen = 9

$(i v)$

Number of $α -$ Hydrogen = 12
Therefore, the stability order will be
$(i v) > (i i i) > (i i) > (i)$

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