CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

The degree of is not well defined.

A
d3ydx3+dydx=ey
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
e(dydx)=k+dydx
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
(1+(dydx)2)=yd3ydx3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
d3ydx3+cosydydx=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B e(dydx)=k+dydx
The degree is clearly defined for the cases d3ydx3+cosydydx=0 and d3ydx3+dydx=ey.
The DE (1+(dydx)2)=yd3ydx3 can be squared on both sides and the degree becomes 2.
Whereas in e(dydx)=k+dydx even after applying ln on both sides we can't reduce to polynomial form.

flag
Suggest Corrections
thumbs-up
0
BNAT
mid-banner-image