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Question

The degree of nk=1(dkydxk)k=0 is.

A
n
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B
k
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C
1
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D
not defined
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Solution

The correct option is A n
The DE looks something like thisdydx+(d2ydx2)2+...+(dnydxn)n=0The highest order derivative is n and its power is n. Hence n is the degree of the DE.

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