The degree of the equation k-1x2 - 3-2x-7- where k - -1 is -

Given that, x^2(k+1)+3/2x=7 Given, k = 1 ⇒ x^2( 1+1)+3/2x=7 ⇒ 3x 14=0 which is not a quadratic equation. ...

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Standard IX

Mathematics

Roots of Quadratic Equation

The degree of...

Question

The degree of the equation $(k + 1) x^{2} + \frac{3}{2} x = 7$ , where k = -1 is .

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Solution

The correct option is A 1
Given that, $x^{2} (k + 1) + \frac{3}{2} x = 7$
Given, k = -1
$\Rightarrow x^{2} (- 1 + 1) + \frac{3}{2} x = 7 \Rightarrow 3 x - 14 = 0$
which is not a quadratic equation.

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Similar questions

The degree of the equation $(k + 1) x^{2} + \frac{3}{2} x = 7$ , where k = -1 is .

What is the degree of following equation?

$(k + 1) x^{2} + \frac{3}{2} x = 7$ , where k = -1

Q. Question 1
Which of the following is a quadratic equation?
(a)

x^{2} + 2 x + 1 = (4 - x)^{2} + 3

(b)

- 2 x^{2} = (5 - x) (2 x - \frac{2}{5})

(c)

(k + 1) x^{2} + \frac{3}{2} x = 7, w h e r e k - = - 1

(d)

x^{3} - x^{2} = (x - 1)^{3}

Question 1
Which of the following is a quadratic equation?
(a) $x^{2} + 2 x + 1 = (4 - x)^{2} + 3$
(b) $- 2 x^{2} = (5 - x) (2 x - \frac{2}{5})$
(c) $(k + 1) x^{2} + \frac{3}{2} x = 7, w h e r e k = - 1$
(d) $x^{3} - x^{2} = (x - 1)^{3}$

Q. Find the value of

a

for which the equation

(k - 1) x^{2} + (k + 4) x + k + 7 = 0

has equal roots.

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The degree of the equation (k+1)x2+32x=7, where k = -1 is .

The correct option is A 1Given that, x2(k+1)+32x=7 Given, k = -1 ⇒x2(−1+1)+32x=7⇒3x−14=0 which is not a quadratic equation.

The degree of the equation $(k + 1) x^{2} + \frac{3}{2} x = 7$ , where k = -1 is .

The correct option is A 1
Given that, $x^{2} (k + 1) + \frac{3}{2} x = 7$
Given, k = -1
$\Rightarrow x^{2} (- 1 + 1) + \frac{3}{2} x = 7 \Rightarrow 3 x - 14 = 0$
which is not a quadratic equation.