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Question
The dehydrogenation of 2-bromo butane with alcoholic KOH gives:
The dehydrogenation of 2-bromo butane with alcoholic KOH gives:
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Solution
The correct option is C 2-butene as the major product
Reaction:
CH3−CH(Br)−CH2−CH3alc.KOH−−−−−→CH3−CH=CH−CH3
According to Saytzeff rule, as 2-butene is a more substituted group, so, it will be formed as a major product.
Reaction:
CH3−CH(Br)−CH2−CH3alc.KOH−−−−−→CH3−CH=CH−CH3
According to Saytzeff rule, as 2-butene is a more substituted group, so, it will be formed as a major product.
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