Question

The dehydrohalogenation of neopentyl bromide with alcoholic KOH mainly gives

• A. 2-methyl-1-butene
• B. 2-methyl-2-butene
• C. 2, 2-dimethyl-1-butene
• D. 2-butene

Answer 1

The correct option is B

2-methyl-2-butene

In this reaction $1^{\circ }$ carbonium ion is formed which rearranges to form $3^{\circ }$ carbonium ion from which base obstruct proton. Hence 2-methyl-2-butene is formed as a main product

$1^{\circ }$ carbonium less stable


2-Methyl-2 Butene