The ΔfH0 for CO2(g),CO(g)andH2O(g) are -393.5, -110.5 and -241.8 kJmol−1 respectively. The standard enthalpy change (in kJmol−1) for the reaction CO2(g)+H2(g)→CO(g)+H2O(g) is :
A
524.1
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B
+ 41.2
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C
-262.5
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D
- 41.2
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Solution
The correct option is B + 41.2 Given, ΔfH0(CO2)=−393.5kJmol−1 ΔfH0(CO)=−110.5kJmol−1 ΔfH0(H2)=−241.8kJmol−1 CO2(g)+H2(g)→CO(g)+H2(g) ΔrH is related to bond enthalpies of reactants and products in the gas phase reaction as ΔrH=∑ΔfH0(products)−∑ΔfH0(reactants)=ΔfH0(CO)+ΔfH0(H2)−ΔfH0(CO2)−ΔfH0(H2)=−110.5−241.8−(−393.5)=+41.20kJmol−1 hence the standard enthalpy change for the given reaction is +41.20kJmol−1