The - G 0 value for the reaction- 2 Mg s - O 2 g - 2 MgO s at 25- C is-Given - S sys 0-217 J K -1 mol -1- - S surr 0-4 kJ K -1 mol -1A- -3780 kJ mol -1B- -3780 Jmol -1C- -1192 kJ mol -1D- -1126 kJ mol -1

The correct option is D – 1126 kJmol^ 1 Δ S^0_Total = Δ S^0_Sys + Δ S^0_surr = + 3.78 kJK^ 1 mol^ 1 ; Δ G^0 = T Δ S^0_Total = 298 × 3.78 = 1126.kJK^ 1 mo ...

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Byju's Answer

Standard XII

Chemistry

Characteristics of Equilibrium Constant

The Δ G 0 val...

Question

The $Δ G^{0}$ value for the reaction, $2 M g_{(s)} + O_{2 (g)} \to 2 M g O_{(s)}$ at $25^{\circ} C$ is,
(Given $Δ S_{s y s}^{0}) = - 217 J K^{- 1} m o l^{- 1}, Δ S_{s u r r}^{0} = 4 k J K^{- 1} m o l^{- 1})$

$+ 3780 J m o l^{- 1}$

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$- 1126 k J m o l^{- 1}$

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$- 1192 k J m o l^{- 1}$

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$- 3780 k J m o l^{- 1}$

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Solution

The correct option is B
$- 1126 k J m o l^{- 1}$

$Δ S_{T o t a l}^{0} = Δ S_{S y s}^{0} + Δ S_{s u r r}^{0} = + 3.78 k J K^{- 1} m o l^{- 1}; Δ G^{0} = - T Δ S_{T o t a l}^{0} = - 298 \times 3.78 = - 1126. k J K^{- 1} m o l^{- 1}$

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The ΔG0 value for the reaction, 2Mg(s)+O2(g)→2MgO(s) at 25∘C is, (Given ΔS0sys)=−217JK−1mol−1,ΔS0surr=4kJK−1mol−1)

The correct option is B –1126kJmol−1 ΔS0Total=ΔS0Sys+ΔS0surr=+3.78 kJK−1mol−1;ΔG0=−TΔS0Total=−298×3.78=−1126.kJK−1mol−1

The $Δ G^{0}$ value for the reaction, $2 M g_{(s)} + O_{2 (g)} \to 2 M g O_{(s)}$ at $25^{\circ} C$ is,
(Given $Δ S_{s y s}^{0}) = - 217 J K^{- 1} m o l^{- 1}, Δ S_{s u r r}^{0} = 4 k J K^{- 1} m o l^{- 1})$

The correct option is B
$- 1126 k J m o l^{- 1}$

$Δ S_{T o t a l}^{0} = Δ S_{S y s}^{0} + Δ S_{s u r r}^{0} = + 3.78 k J K^{- 1} m o l^{- 1}; Δ G^{0} = - T Δ S_{T o t a l}^{0} = - 298 \times 3.78 = - 1126. k J K^{- 1} m o l^{- 1}$