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Question

Calculate the change in entropy for the following reaction 
2CO(g)+O2(g)2CO2(g).
Given S0CO2=213.6JK1mol1,S0CO=297.6JK1mol1 respectively.
 



A

-185.03 JK1mol1

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B

-143.03 JK1mol1

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C

-173.03 JK1mol1

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D

None of these

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Solution

The correct option is D

-173.03 JK1mol1


Since, entropy is a state function,
S = SfinalSinitial
For chemical reactions,
S = S (products) - S (reactants)
Therefore,
            =[2×SCO2(g)2×SCO+SO2
            =(213.6×2)(2×197.6+205.03)
          =427.2600.23=173.03 JK1mol1


Chemistry

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