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Question

The entropy (So) of the following substances are:
CH4(g)=186.2 JK1mol1
O2(g)=205.0 JK1mol1
CO2(g)=213.6 JK1mol1
H2O(l)=69.9 JK1mol1

The entropy change (ΔSo) for the reaction CH4(g)+2O2(g)CO2(g)+2H2O(l) is:

A
312.5 JK1mol1
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B
242.8 JK1mol1
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C
108.1 JK1mol1
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D
37.6 JK1mol1
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Solution

The correct option is C 242.8 JK1mol1
Given:
CH4(g)=186.2 JK1mol1
O2(g)=205.0 JK1mol1
CO2(g)=213.6 JK1mol1
H2O(l)=69.9 JK1mol1

The entropy change (ΔSo) for the reaction CH4(g)+2O2(g)CO2(g)+2H2O(l)

Entropy of a reaction = entropy of products entropy of reactants
Here, entropy change, ΔS=(213.6+2×69.9)(186.2+2×205)=242.8 JK1mol1

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