The density for an FCC lattice is:

[A = atomic wt, N = Avogadro's number, a = lattice parameter]

\frac{4 A}{N a^{3}}

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\frac{2 A}{N a^{3}}

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\frac{A}{N a^{3}}

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\frac{A}{N a^{2}}

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Solution

The correct option is A $\frac{4 A}{N a^{3}}$
In $F C C$ lattice, the no. of atoms per unit cell $= 4$

Density $= \frac{m a s s o f u n i t c e l l}{v o l u m e o f u n i t c e l l} = \frac{4 A / N}{a^{3}} = \frac{4 A}{N a^{3}}$

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