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Question

The density of 3 M sodium thiosulphate is 1.25 g/ml. Identify the correct statements among the following.

A
% by weight of sodium thiosulphate is 37.92
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B
The mole fraction of sodium thisoulphate is 0.065
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C
The molarity of Na+ is 2.53 and S2O23 is 1.25
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D
Both (A) and (B)
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Solution

The correct option is D Both (A) and (B)
The molecular weight of sodium thiosulphate pentahydrate = 248.
1000 ml of 3 M solution contains 248×3 g thiosulphate.
1 ml of 3 M solution contains 248×31000 g or 0.744 g thiosulphate.
Amount of water per ml of aqueous thiosulphate solution
=1.250.744=0.506 g .
Mole fraction of thiosulphate = (mole of thiosulphate)/(total number of moles)
=(0.744/248)(0.744/248)+(0.506/18)
=0.003(0.003+0.02811)
=0.0964 .
Molarity of sodium & thiosulphate ions:
One molecule of thiosulphate gives 2 atoms of sodium ;
One mole of thiosulphate gives 2 moles of sodium ;
1000 ml of 3M thiosulphate will give 2× 3 gram-atoms or 6 gram-atoms of sodium and 3 moles of thiosulphate ions.
Hence, option (D) is correct option

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