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Concentration Terms - An Introduction (w/w etc)

The density o...

Question

The density of 3M solution of $N a_{2} S_{2} O_{3}$ is $1.25$ g mL $^{- 1}$ . Calculate, mole fraction of $N a_{2} S_{2} O_{3}$ .

A

0.065

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B

0.165

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C

0.015

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D

0.265

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Solution

The correct option is A $0.065$
Given $N a_{2} S_{2} O_{3} has molarity = 3 m o l L^{- 1}$
$∴$ Mole of $N a_{2} S_{2} O_{3} = 3$
$∴$ $Weight of N a_{2} S_{2} O_{3} = 3 \times 158 = 474 g$
and V of solution $=$ 1 litre $= 1000$ mL
$∴ Weight of solution = 1000 \times 1.25 = 1250 g$
$∴ Weight of water = 1250 - 474 = 776 g$
$Mole fraction ofNa2S2O3=Mole of Na2S2O3Mole of Na2S2O3+mole of H2O$
$= \frac{3}{3 + \frac{776}{18}} = 0.065$

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