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Ideal Gas Equation

The density o...

Question

The density of a gas is $2$ g/L at $1$ atm and $27^{0}$ C. The density of the same gas at $2$ atm and $127^{0}$ C is:

3 g / L

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1.33 g / L

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2 g / L

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1 g / L

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Solution

The correct option is A $3 g / L$
$As, P = \frac{d R T}{M} \Rightarrow \frac{d_{1} T_{1}}{P_{1}} = \frac{d_{2} T_{2}}{P_{2}} \Rightarrow \frac{(2) (300 K)}{1} = \frac{d_{2} (400)}{2} \Rightarrow d_{2} = 3 g / L$

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Similar questions

The density of a gas is 2 $\frac{g}{L}$ at 1 atm and $27^{0} C$ . The density of the same gas at 2 atm and $127^{0} C$ is:

2.5

127^{0}

1

127^{o}

O_{2}

1.6

a = 4.0

L^{2}

m o l^{- 2}

0.4

m o l^{- 1}

= 0.08

O_{2}

127^{o} C

4.0

R = 0.082 L a t m K^{- 1} m o l^{- 1}

27^{0}

C

1.8

g / L

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