The density of a substance is $7100 k g m^{- 3}$ . It's relative density is:

7100

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71

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7.1

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71 \times 10^{5}

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Solution

The correct option is C $7.1$
Relative density, or specific gravity, is the ratio of the density (mass of a unit volume) of a substance to the density of a water.
So, $R e l a t i v e d e n s i t y = \frac{D e n s i t y o f s u b s t a n c e}{D e n s i t y o f w a t e r}$
$\Rightarrow \frac{7100 k g m^{- 3}}{1000 k g m^{- 3}} = 7.1$

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Similar questions

(a) What is the difference between the density and relative density of a substance?
(b) If the relative density of a substance is 7.1, what will be its density in SI units?

Which of the following statement(s) is/are true about relative density?
Statement 1: Relative density is known as the specific gravity of the substance.
Statement 2: Relative density of a substance is the ratio of the density of the substance to the density of water at $4^{\circ} C$ .
Statement 3: Relative density of a substance is the ratio of the mass of water at $4^{\circ} C$ to the mass of a substance at $4^{\circ} C$ .
Statement 4: Relative density is unitless.

Relative density of a substance is expressed by comparing the density of that substance with density of:

Q. How are the relative density and the density of a substance related? What is the unit of relative density?

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The density of a substance is 7100kgm−3. It's relative density is:

The correct option is C 7.1Relative density, or specific gravity, is the ratio of the density (mass of a unit volume) of a substance to the density of a water. So, Relativedensity=DensityofsubstanceDensityofwater⇒7100kgm−31000kgm−3=7.1

The density of a substance is $7100 k g m^{- 3}$ . It's relative density is: