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Concentration Terms - An Introduction (w/w etc)

The density o...

Question

The density of air at pressure of $10^{5} N m^{- 2}$ is $1.2 k g m^{- 3}$ . Under these conditions the root mean square velocity of the air molecules is $m s^{- 1}$ is

500

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1000

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1500

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3000

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Solution

The correct option is C $500$
$C = \sqrt{\frac{3 P}{ρ}}$ (standard result)
$= \sqrt{\frac{3 \times 10^{5}}{1.2}}$
$= 500 m s^{- 1}$

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