The density of copper is 8-9 -3- What will be its density in -3 -

Given, Density, d = 8.9 𝑔𝑐𝑚^−3 As we know that, 1 𝑔 = 10^−3 𝑘𝑔 and 1 𝑐𝑚^3 = 10^−6 𝑚^3 So, nbsp; d = 8.9 𝑔𝑐𝑚^−3 = 8.9 × 10^−3 𝑘𝑔10^−6 𝑚^3 = 8900 𝑘𝑔𝑚^−3 Hen ...

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The density o...

Question

The density of copper is $8.9 g c m^{- 3}$ . What will be its density in $k g m^{- 3}$ ?

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Solution

Given,
Density, $d = 8.9 g c m^{- 3}$
As we know that, $1 g = 10^{- 3} k g$
and $1 c m^{3} = 10^{- 6} m^{3}$
So, $d = 8.9 g c m^{- 3}$
$= \frac{8.9 \times 10^{- 3} k g}{10^{- 6} m^{3}}$
$= 8900 k g m^{- 3}$
Hence, $d = 8900 k g m^{- 3}$

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Q. A lump of copper of mass 890 g is dipped into a glass filled to the brim with water. What volume of water will overflow? (The density of copper = 8.9 g/cm³.)

The density of water is $1000 k g / m^{3}$ and the density of copper. is $8900 k g / m^{3}$ . Which of the following statements is incorrect ?

(a) $\frac{The density of a certain volume of copper}{The density of the same volume of water} = 8.9$
(b) $\frac{The volume of a certain mass of copper}{The volume of the same mass of water} = 8.9$
(c) $\frac{The weight of a certain volume of copper}{The weight of the same volume of water} = 8.9$
(d) $\frac{The mass of a certain volume of copper}{The mass of the same volume of water} = 8.9$

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The density of copper is 8.9 gcm−3. What will be its density in kgm−3 ?

Given, Density, d=8.9 gcm−3 As we know that, 1 g=10−3 kg and 1 cm3=10−6m3 So, d=8.9 gcm−3 =8.9×10−3 kg10−6 m3 =8900 kgm−3 Hence, d=8900 kgm−3

The density of copper is $8.9 g c m^{- 3}$ . What will be its density in $k g m^{- 3}$ ?

Given,
Density, $d = 8.9 g c m^{- 3}$
As we know that, $1 g = 10^{- 3} k g$
and $1 c m^{3} = 10^{- 6} m^{3}$
So, $d = 8.9 g c m^{- 3}$
$= \frac{8.9 \times 10^{- 3} k g}{10^{- 6} m^{3}}$
$= 8900 k g m^{- 3}$
Hence, $d = 8900 k g m^{- 3}$