Question

The density of ice is $917kg{m}^{-3}.$ What fraction of ice lies below water? The density of sea water is $1024kg{m}^{-3}.$ What fraction of the iceberg do we see assuming that it has the same density as ordinary ice $\left(917kg{m}^{-3}\right)?$

Answer 1

The weight of the iceberg=buoyancy force

$V_1\rho g=mg=V_2\rho g$

By substituting the values in the above equation we get

$V_{1}1024=917V_2$

$V_1=089V_2$

The fraction of the visible iceberg is

$V=V_2-V_1$

Hence the visible fraction is$0.11V_2$