The density of iron is 7-8- 103kg m-3- Its relative density is X- Find X-

The correct option is A 7.8 RD = density of irondensity of water RD = 7.8 × 10^3 kgm^ 310^3 kgm^ 3 ⇒ RD = 7.8 ...

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Standard IX

Physics

Relative Density

The density o...

Question

The density of iron is $7.8 \times 10^{3} k g m^{- 3}$ . Its relative density is X. Find X.

7.8

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Solution

The correct option is A $7.8$
$R D = \frac{d e n s i t y o f i r o n}{d e n s i t y o f w a t e r}$
$R D = \frac{7.8 \times 10^{3} k g m^{- 3}}{10^{3} k g m^{- 3}}$
$\Rightarrow R D = 7.8$

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What do you mean by this statement :

The density of iron is 7.8gm cm^-3

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The density of iron is 7.8×103kgm−3. Its relative density is X. Find X.

The correct option is A 7.8RD=densityofirondensityofwaterRD=7.8×103kgm−3103kgm−3⇒RD=7.8

The density of iron is $7.8 \times 10^{3} k g m^{- 3}$ . Its relative density is X. Find X.

The correct option is A $7.8$
$R D = \frac{d e n s i t y o f i r o n}{d e n s i t y o f w a t e r}$
$R D = \frac{7.8 \times 10^{3} k g m^{- 3}}{10^{3} k g m^{- 3}}$
$\Rightarrow R D = 7.8$