Question

The depletion layer in a silicon diode is $1\mu \text{m}$ wide and the knee potential is $0.6\text{V}$, then the electric field in the depletion layer will be

• A. Zero
• B. $0.6{\text{Vm}}^{-1}$
• C. $6\times {10}^4{\text{Vm}}^{-1}$
• D. $6\times {10}^5{\text{Vm}}^{-1}$

Answer 1

The correct option is D $6\times {10}^5{\text{Vm}}^{-1}$

We know

$|E|=\frac{\Delta V}{\Delta x}\text{(Potential gradient)}$

$\Rightarrow E=\frac{0.6}{1\times {10}^6}$

$\Rightarrow E=6\times {10}^5{\text{Vm}}^{-1}$

Hence, $\left(D\right)$ is the correct answer.