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Question

The derivative of eln(sinx) with respect to x where x(0,π2), is

[1 mark]

A
eln(sinx)cosx
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B
cosx
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C
esinx
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D
ecosx
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Solution

The correct option is B cosx
Let y=eln(sinx)
As we know alogam=m,
y=sinx
Differentiating w.r.t. x, we get
dydx=cosx

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