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Question

# The diameter of the droplet is 0.075 mm. What is the intensity of pressure (N/sq.cm) developed in the droplet by the surface tension of 0.000075 N/mm?

A
0.4
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B
0.6
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C
0.8
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D
1
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Solution

## The correct option is A 0.4 Let the pressure difference between inside and outside be ΔP . Let the droplet be cut into two halves As there is only one interface between liquid and air, πdσ=πd24×ΔP ΔP=4σd Where σ = Surface tension d= diameter of droplet The smaller is the diameter of the bubble layer, the larger is the pressure difference. Note: Data Given: Surface tension, σ= 0.000075 N/mm Diameter of the droplet, (d)=0.075 mm ΔP=4×0.0000750.075 =4×10−3N/mm2=0.4 N/cm2 Note: Soap Bubble in Air In a soap bubble, there are two interfaces between soap film and air. One inside the bubble and the other outside. Hence, (2πrσ)×2=ΔP×πr2 ⇒ΔP=4σr Liquid Jet : Consider a liquid jet of dia 'd' and length 'l'

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