Question

The difference between the ages of two cousins is 10 years. 15 years ago, if the elder one was twice as old as the younger one, find their present ages.

Answer 1

Dear Student.

$$\begin{gathered} Letthepresentageoffirstcou\sin bex \\ presentageofsecondcou\sin willbex+10 \\ ageoffirstcou\sin before15years=x-15 \\ ageofsecondcou\sin before15years=x-5 \\ Accordingtoquestion:2(x-15)=x-5 \\ 2x-30=x-5 \\ x=25 \\ Soageoffirstcou\sin =25yearsandsecondcou\sin =35years \end{gathered}$$

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