Question

The difference between the ages of two cousins is 10 years. 15 years ago, if the elder one was twice as old as the younger one, find their present ages.

Answer 1

Let age of elder cousin = x years

and age of younger = (x - 10) years.

15 years ago,

age of older, cousin = x - 15 years

and age of younger = x - 10 - 15

= (x - 25) years.

According to the condition,

x - 15 = 2 (x - 25) $\Rightarrow$ x - 15 = 2x - 50

$\Rightarrow$ 2x - x = 50 - 15 $\Rightarrow$ x = 35

$\therefore$ Age of elder cousin = 35 years

and age of younger = 35 - 10

= 25 years Ans.