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Question

the difference between two sisters, ages is 5 year, of 10 year ago, if the elder one was twice as old as young one, find their present age.

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Solution

Dear student,
Let the age of younger sister be 'x'then the age of elder sister be (x+5)10 yrs ago,(x+5)-10=2(x-10)x-5=2x-20x-2x=-20+5-x=-15x=15thus the present age of younger sister is 15 yrsand the present age of elder sister is 15+5=20 yrs
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