The difference in age between a girl and her younger sister is $4$ years.The younger sister, in turn, is $4$ years older than her brother. The sum of the ages of the younger sister and her brother is $16 .$ How old are the three children?

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Solution

Let the age of girl is x.
So age of younger sister $x - 4$ & brothers age is $x - 8$
Given,
$x - 4 + x - 8 = 16$
$2 x - 12 = 16$
$2 x = 28$
$x = 14$
So age is $14, 10, 6$ .

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The difference in age between a girl and her younger sister is 4 years.The younger sister, in turn, is 4 years older than her brother. The sum of the ages of the younger sister and her brother is 16. How old are the three children?

Let the age of girl is x.So age of younger sister x−4 & brothers age is x−8Given,x−4+x−8=162x−12=162x=28x=14So age is 14,10,6.

The difference in age between a girl and her younger sister is $4$ years.The younger sister, in turn, is $4$ years older than her brother. The sum of the ages of the younger sister and her brother is $16 .$ How old are the three children?

Let the age of girl is x.
So age of younger sister $x - 4$ & brothers age is $x - 8$
Given,
$x - 4 + x - 8 = 16$
$2 x - 12 = 16$
$2 x = 28$
$x = 14$
So age is $14, 10, 6$ .