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Question

The difference in limiting molar conductivity between KCl and KNO3 is the same as the difference between :

A
NaCl and KNO3
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B
KCl and NaCl
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C
NaCl and NaNO3
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D
KNO3 and NaNO3
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Solution

The correct option is C NaCl and NaNO3
Kohlrausch law:
At infinite dilution, when all the interionic effects disappear and dissociation of electrolyte is complete, each ion makes a definite contribution towards equivalent conductance of the electrolyte irrespective of the nature of the ion with which it is associated.

Kohlrausch law of independent migration of ions:
Λ0m=λ0++λ0

λ0+Limiting molar conductivities of cation
λ0Limiting molar conductivities of anion

For KCl and KNO3
Λ0KCl=λ0K++λ0Cl
Λ0KNO3=λ0K++λ0NO3

Λ0KClΛ0KNO3=λ0Clλ0NO3....(1)
The obtained value is due to the difference in λm of Cl and NO3 ions.

For NaCl and NaNO3,
Λ0NaCl=λ0Na++λ0Cl
Λ0NaNO3=λ0Na++λ0NO3

Λ0NaClΛ0NaNO3=λ0Clλ0NO3....(2)
The obtained value is due to the difference in λm of Cl and NO3 ions.
This proves the Kohlrausch law of independent migration of ions.

Hence, correct option is (a)

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