The differential equation for a family of curves is dydx=y2x. What is the differential equation for the orthogonal trajectory of the curves?
A
dydx=−y2x
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B
dydx=−2xy
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C
dydx=2xy
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D
dydx=yx
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Solution
The correct option is Bdydx=−2xy The given differential equation is dydx=y2x. The slope of the tangent of given family of curves is y2x. So, the orthogonal trajectory will have slope −1(y2x) as m1m2=−1. Thus the differential equation of the required orthogonal trajectory is dydx=−2xy.