The digit at the ten's place of a two digit number is four times that in the unit's place. If the digits are reversed, the new number will be $54$ less than the original number. Find the original number.

28

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82

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41

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14

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Solution

The correct option is A $82$
$L e t t h e n u m b e r b e x y ∴ x = 4 y ⟶ (1.) a n d 10 y + x = (10 x + y) - 54 9 y - 9 x = - 54 x - y = 6 o r 4 y - y = 6 y = 2 t h e n x = 8 ∴ n u m b e r i s 82$

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The digit at the ten's place of a two digit number is four times that in the unit's place. If the digits are reversed, the new number will be 54 less than the original number. Find the original number.

The correct option is A 82Letthenumberbexy∴x=4y⟶(1.)and10y+x=(10x+y)−549y−9x=−54x−y=6or4y−y=6y=2thenx=8∴numberis82

The digit at the ten's place of a two digit number is four times that in the unit's place. If the digits are reversed, the new number will be $54$ less than the original number. Find the original number.

The correct option is A $82$
$L e t t h e n u m b e r b e x y ∴ x = 4 y ⟶ (1.) a n d 10 y + x = (10 x + y) - 54 9 y - 9 x = - 54 x - y = 6 o r 4 y - y = 6 y = 2 t h e n x = 8 ∴ n u m b e r i s 82$