Question

The digit in the ten's place of a two-digit number is three times that in the one's places if the digits are reversed the new number will be 36 less than the original number Find the number

• A. 64
• B. 52
• C. 62
• D. 42

Answer 1

The correct option is C 62

Let the digits be $x$ and $y$
Given, "The digit in the ten's place of a two-digit number is three times that in the one's places "
$=>x=3y$

Now, when the digits are reversed, the number will be $10y+x$
Also, if the digits are reversed the new number will be $36$ less than the original number. $=>10y+x=(10x+y)-36$
$=>9x-9y=36$
Putting $x=3y$ in this,
$9\left(3y\right)-9y=36$
$=>27y-9y=36$
$18y=36=>y=2$
So, $x=3y=6$
Hence, the number is $62$