The digit in the units place of [(251)98+(21)29−(106)100+(705)35−(16)4+259] is
A
1
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B
4
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C
5
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D
6
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Solution
The correct option is B 4 Unit digit of (251)98 = 1 Unit digit of (21)29 = 1 Unit digit of (106)100 = 6 Unit digit of (705)35= 5 Unit digit of (16)4 =6 Unit digit of 259 = 9
The digit in the units place of [(251)98+(21)29−(106)100+(705)35−(16)4+259] is 1+1-6+5-6+9 =4