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Question

The digit in the units place of [(251)98+(21)29(106)100+(705)35(16)4+259] is

A
1
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B
4
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C
5
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D
6
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Solution

The correct option is B 4
Unit digit of (251)98 = 1
Unit digit of (21)29 = 1
Unit digit of (106)100 = 6
Unit digit of (705)35= 5
Unit digit of (16)4 =6
Unit digit of 259 = 9
The digit in the units place of [(251)98+(21)29(106)100+(705)35(16)4+259] is 1+1-6+5-6+9 =4

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