The digit in the units place of $6789^{5}$ is

6

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7

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8

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9

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Solution

The correct option is D $9$
If we divide 5 by 4 then we will get reminder 1 so the last digit of $6789^{5} = 9$

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Similar questions

7^{291}

Sum of digit of two number is 8. The digit in tens place is thrice the digit in unit place in unit place. Find the numbers?

What is the digit at units place of 9^9.

(56)^{9}

7^{1}

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